A body is moving with uniform velocity of 2 m s1
on a
rough level surface. The frictional force on it is 10 N. If
the body moves with velocity 4 m s1 the force of
friction will be:
(a) 2.5 N (b) 5 N
(c) 10 N (d) 20 N
Answers
Answered by
0
is this your answer?
Attachments:
Answered by
1
Hey dear,
◆ Answer-
F2 = 20 N
◆ Explanation-
# Given-
v1 = 2 m/s
v2 = 4 m/s
F1 = 10 N
# Solution-
As we know, frictional force depends on the velocity of the moving object.
i.e. F ∝ v
Thus, here-
F1/v1 = F2/v2
F2 = F1 × v2 / v1
F2 = 10 × 4 / 2
F2 = 20 N
Therefore, frictional force is 20 N.
Hope it helps...
◆ Answer-
F2 = 20 N
◆ Explanation-
# Given-
v1 = 2 m/s
v2 = 4 m/s
F1 = 10 N
# Solution-
As we know, frictional force depends on the velocity of the moving object.
i.e. F ∝ v
Thus, here-
F1/v1 = F2/v2
F2 = F1 × v2 / v1
F2 = 10 × 4 / 2
F2 = 20 N
Therefore, frictional force is 20 N.
Hope it helps...
Similar questions