Question

A body is moving with variable acceleration (a) along a straight line. The average acceleration of body in time interval t1 and t2 is

Answer 1

THE ACCELERATION OF T2WILL BE LESSER THAN OF T1 BECAUSE THE PARTICLE OF T2WILL WILL BE ROTATE FROM NEGATIVE BUT T1 WILL ROTATE IN POSITIVE .

SO. T1 GREATER THAN OF T2.

Answer 2

Average acceleration can be equal to difference of final velocity and initial velocity divided by time interval, or it can also be equal to the sum of initial and final accelerations divided by 2.
Mathematically,
Let u and v be the initial and final velocities, a1 and a be the initial and final accelerations,
Avg acceleration= (v-u)/t2-t1
Or
Avg acceleration= (a2-a1)/2

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