Question

A body is moving with velocity 20m/s2 if some one provides acceleration of 5 m/s2 for 4 sec its velocity becomes​

Answer 1

Explanation:

5x−1=5x−55x−1=5x−5

⟹5x−1=5(5x−1−1)⟹5x−1=5(5x−1−1)

⟹5x−2=5x−1−1⟹5x−2=5x−1−1

⟹5x−1−5x−2=1⟹5x−1−5x−2=1

⟹5x−2(5−1)=1⟹5x−2(5−1)=1

⟹4⋅5x−2=14⟹4⋅5x−2=14

⟹(x−3)=log514⟹(x−3)=log5⁡14

⟹x−2=−2log52⟹x−2=−2log5⁡2

⟹x=2−2log52⟹x=2−2log5⁡2

⟹x≈2−2(0.431)⟹x≈2−2(0.431)

⟹x≈2−0.862⟹x≈2−0.862

⟹x≈1.138

Answer 2

Answer:

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