Physics, asked by agb36, 1 year ago

A body is moving with velocity 30m/S towards east . After 10s its velocity becomes 40m/s towards north. The average acceleration of the body is

A)7 m/s
B)5 m/s
C)2 m/s
D)8 m/s​

Answers

Answered by vinit7777
5

Answer:

CORRECT ANSWER IS B 5m/s^2

Explanation:

REFER TO THE ATTACHMENT...HOPE IT HELPS. PLEASE MARK IT AS BRAINLIEST...

Attachments:
Answered by ShivamKashyap08
10

\huge{\underline{\underline{.........Answer.........}}}

\huge{\underline{Given:-}}

It is moving 30m/s towards east.

and, 40 m/s towards North.

\huge{\underline{Explanation:-}}

Taking east as x axis and North as y axis as they are mutually perpendicular.

{initial velocity \vec{v_i} = 30 \hat{i} \:in east direction}

{Final velocity \vec{v_f} = 40 \hat{j} \:in east direction}

Now from acceleration

\huge{\boxed{\boxed{a =  \frac{|v_f - v_i|}{t}}}}

{a =  \frac{40 \hat{j} - 30\hat{i}}{10}}

Their magnitude should be taken.

{a = \frac{ \sqrt{ {40}^{2} + {30}^{2}  } }{10}}

{ a = \frac{ \sqrt{1600 + 900} }{10}}

{a = \frac{ 50 }{10}}

{a =5 m/s^2}

\huge{\boxed{\boxed{a = 5 m/s^2}}}

\huge{\boxed{\boxed{option - B}}}

so, acceleration of the body is 5m/s^2.

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