Physics, asked by lubna165, 11 months ago

. A body is pivoted at a point. A force of 10 N is
applied at a distance of 30 cm from the pivot.
Calculate the moment of force about the pivot.​

Answers

Answered by stylishtamilachee
25

Answer:

The moment of force is 3 N m.

Explanation:

Given:

Force or F = 10 N

Distance from pivot or r = 30 cm

= 30 / 100 = 0.3 m.

To find:

The Moment of force = ?

Solution:

The moment of force = force (f) x distance from pivot (r)

Therefore,

Moment of force = F x r

Moment of force = 10 x 0.3

= 3 N m.

Moment of force:

  • The moment of force is the measure of the turning effect of force on a body.

  • It is also called torque or moment.

  • It is given by the product of the magnitude of the force and the perpendicular distance of the line of action of the force from the pivot..

Moment of force (M) = force (F) x perpendicular distance of force from pivot (r).

Answered by Anonymous
51

Answer:

3 Nm

Explanation:

Moment of force is calculated as:

Force x (perpendicular distance between point of application of force and axis of rotation)

But the unit should of the same system, SI or CGS

Here, Force = 10 N

Distance = 30/100 = 0.3 m

Hence, Moment of force = 10x0.3 Nm

= 3 Nm

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