Question

a body is projected along a rough horizontal surface with 6 m/s comes to rest after travelling a distance of 9m. Find the coefficient of friction(g=10m/s^2)
please answer it !!!!!

Answer 1

Answer:

Explanation:

Phele 6m/s ko 9m me divide krna or fir jo answer aay Usko calculate krna frictional force se

Answer 2

The coefficient of friction is given by µ which is equal to Frictional force by normal force.

Here we know due to friction body is decelerating now the formula that will be used here is  

Ma-µg= 0 {Where M is mass is deceleration you is coefficient of friction and R=mg}

Ma = µmg

A = µg

To find acceleration applying Newton’s law of motion

$\begin{array}{l}{A=\frac{v^{2}-u^{2}}{2 s}=-\frac{36}{2 x 9}=-2 m / s^{2}} \\ {\mu=\frac{a}{g}=-.2}\end{array}$