Question

a body is projected along a rough horizontal surface with 6m/s comes to rest after travelling a distance 9m.the coefficient of sliding friction is(g=10m/s^2

Answer 1

If you want to 6m/s divided by 9m fir jo answer aay usko frictional force se calculate krna

Answer 2

Answer:

The coefficient of sliding friction is 0.2.

Explanation:

Given that,

Velocity = 6 m/s

Distance = 9 m

We need to calculate the acceleration

Using equation of motion

$v^2=u^2+2as$

Put the value into the formula

$0=6^2-2\times a\times 9$

$a=\dfrac{6^2}{2\times9}$

$a=2 m/s^2$

We need to calculate the coefficient of sliding friction

Using newton's second law

$F = ma$...(I)

Using formula of friction

$F = \mu mg$...(II)

From equation (I) and (II)

$\mu mg=ma$

$\mu=\dfrac{a}{g}$

$\mu=\dfrac{2}{10}$

$\mu=0.2$

Hence,  The coefficient of sliding friction is 0.2.