a body is projected an angle theta with respect to horizontal direction with velocity V to the maximum range of the body is. please friends and Sarath fast!!
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The answer will be the same here too !!
Range = v^2 * sin 2theta / g
Here, the velocity is just v instead of u.
Since the maximum value of sin2theta = 1
Max range = v^2/g
Range = v^2 * sin 2theta / g
Here, the velocity is just v instead of u.
Since the maximum value of sin2theta = 1
Max range = v^2/g
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