Question

- A body is projected at 60° with the horizonta
with velocity of 10v3 ms. The velocity of
the projectile when it moves perpendicular to
its initial direction is​

Answer 1

Answer:

ans is v sin theta = 10v3×sin60 so put the value get the ans

Answer 2

Explanation:

theta=60 degrees

u=10 root 3 m/s

v=ucot theta

10 root 3 ×cot 60

=10m/s