A body is projected at an angle 30° to the horizontal with a speed of 30 ms. The angle made by
the velocity vector with the horizontal after 1.5 s is (g-10 ms )
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Answer:
The angle made by velocity vector with the horizontal after 1.5s will be 14° 48
Explanation:
We have to find the time of flight first
T=2usintheta/g
=2×30×sin theta/10
15/60= sin theta
sin theta = 1/4= 14° 48
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