Question

A body is projected at an angle theta with the horizontal. When it is at the highest point, the ratio of the potential and kinetic energies of the body is

Answer 1

Answer:

the ratio PE:KE= tan^2(theta) at the highest point

Answer 2

Answer:

the correct answer is tan^2 theta

Explanation:

(b) Potential energy PE

=mgh(max)=mg(u^2sin^(2)θ)/2g=μ^2sin^(2)θ/2

KE=1/2m(ucosθ)^2

Here PE/KE=tan^(2)θ