A body is projected at an angle theta with the horizontal velocity u. Derive an expression for its 1) time of flight 2)horizontal range
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For time of flight u = u sin theta and v = - usin theta
Now put in equation 1 of motion and get t
And for horizontal range = u cos theta * time of flight
Now put in equation 1 of motion and get t
And for horizontal range = u cos theta * time of flight
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