Question

A body is projected at an angle theta with the horizontal another body is projected with the same velocity at an angle theta with the vertical the ratio of the time of flights is

Answer 1

T= 2u sin(theta) / g

T1=2u sin(theta) / g-----------------(1)

for second case we have theta with horizontal

  therefor angle with vertical is (90-theta)

T2=2u sin(90-theta) / g----------------(2)

divide (1) and (2)

T1 / T2 = sin(theta) / sin(90-theta)

T1 / T2 =sin (theta) / cos (theta)

T1 / T2= tan(theta)

therefore ratio of time of flights is tan(theta)

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