Question

A body is projected at an angle to the horizontal with kinetic energy Ek,. The potential energy at the highest
point of the trajectory is:
1.Ek 2.Ekcos^2theta 3.Eksin^2theta 4.Ektan^2theta​

Answer 1

Answer:

3

Explanation:

At highest point, height will be maximum .

Since vertical component of velocity will be responsible for maximum height,

The potential energy at that point will be mgH = (1/2)m(vsinθ)^2

= (1/2)mv^2(sinθ)^2

= Ek(sinθ)^2