a body is projected at such an angle that the horizontal range is three times the greatest height the angle of projection is
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★Hi , Everyone !!!!★
R = u²sin 2∅ / g = 3 H = 3 u² sin² ∅ /2g
=> u² sin2∅ /g = 3u² sin²∅/2g
=> 2sin∅ cos∅ = 3sin² ∅/ 2
2sin∅ Cos∅ = 3 sin∅ /2
tan ∅ = 4 / 3
∅ => tan ^ -1 ( 4 / 3 )
hope it helps you!!!
thanks !!!
★Ranjan Kumar ★
R = u²sin 2∅ / g = 3 H = 3 u² sin² ∅ /2g
=> u² sin2∅ /g = 3u² sin²∅/2g
=> 2sin∅ cos∅ = 3sin² ∅/ 2
2sin∅ Cos∅ = 3 sin∅ /2
tan ∅ = 4 / 3
∅ => tan ^ -1 ( 4 / 3 )
hope it helps you!!!
thanks !!!
★Ranjan Kumar ★
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