A body is projected at velocity of 40 m/s, after 2 sec it crosses a vertical pole of height 20.4 m...
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U = 40 m/s g = 9.8 m/s
At t1 = 2 sec y = 20.4 m
y = u sinФ t - g t² /2
20.4 = 40 sinФ * 2 - g 2² /2
=> sinФ = 1/2
=> Ф = 30°
Horizontal range = R = u² Sin2Ф / g = 40² sin60° / 9.8 = 141.39 m
At t1 = 2 sec y = 20.4 m
y = u sinФ t - g t² /2
20.4 = 40 sinФ * 2 - g 2² /2
=> sinФ = 1/2
=> Ф = 30°
Horizontal range = R = u² Sin2Ф / g = 40² sin60° / 9.8 = 141.39 m
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