Question

A body is projected at velocity v making an angle tetha with the horizontal its velocity whdn it is perpendicular to initial velocity vector is

Answer 1

Explanation:

Given,

Projected velocity, v

angel,     θ

Velocity at any time t

  Vt=vcosθi^+(vsinθ−gt)j^

tan a

$\tan \: a = \frac{v \sin \: θ - gt }{v \cos }$

 (at t=1)tan α

$= > \frac{v \sin - gt}{v \cos }$

Angle at time 1 sec from start α=tan−1