Question

a body is projected from a height vertically upwards. another body is dropped with the same height . the acceleration of the 1st body relative to the other is?

Answer 1

Given:

A body is projected from a height vertically upwards while another body is dropped with the same height.

To find:

Acceleration of 1st body w.r.t the other.

Calculation:

Acceleration experienced by the 1st body:

$\therefore \: \vec{a1} = g \: \: ( - \hat{j})$

Acceleration experienced by the 2nd body:

$\therefore \: \vec{a2} = g \: \: ( - \hat{j})$

Relative acceleration of 1st body w.r.t to 2nd body:

$\therefore \: \vec{a_{12}} = \vec{a1} - \vec{a2}$

$= > \: \vec{a_{12}} = g \: ( - \hat{j})- g \: ( - \hat{j})$

$= > \: \vec{a_{12}} = 0 \: m {s}^{ - 2}$

So, the acceleration of the 1st body relative to 2nd body is 0 m/s² (zero).

Answer 2

Answer:

hi aogi???.....kab mujhse intezaar nahi hota... :(