Question

A body is projected horizontal with a velocity of 10m/s from a high of 1km. Findout the time of flying and horizontal range.​

Answer 1

$\huge{\star}{\underline{\boxed{\red{\sf{Answer :}}}}}{\star}$

Given :-

Velocity (v) = 10 m/s

Height (h) = 1km = 1000 m

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To Find :-

Time of Flight and Horizontal Range

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Solution :-

We have formula for Maximum height :-

$\Huge{\boxed{\boxed{\orange{\sf{T \: = \: \sqrt{\frac{2h}{g}}}}}}}$

Put g as 10 m/s² ,and put other values

$\Large \leadsto {\sf{T \: = \: \sqrt{\frac{2(100)}{10}}}}$

$\Large \leadsto {\sf{T \: = \: \sqrt{\frac{\cancel{2000}}{\cancel{10}}}}}$

$\Large \leadsto {\sf{T \: = \: \sqrt{200}}}$

$\Huge \implies {\boxed{\boxed{\sf{T \: = \: 14 \: s}}}}$

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$\Huge{\boxed{\boxed{\orange{\sf{R \: = \: v \sqrt{\frac{2h}{g}}}}}}}$

As value of $\large{\sf{\sqrt{\frac{2h}{g}}}}$ is 14

So,

$\Large \leadsto{\sf{R \: = \: (10)(14)}}$

$\Huge{\boxed{\boxed{\sf{R \: = \: 140 \: m}}}}$