a body is projected horizontally from the top of a hill with 30.If g=10ms power -1 the velocity of that body after 4 seconds is
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Question :--- a body is projected horizontally from the top of a hill with 30m/s .. If g=10m/s² , the velocity of that body after 4 seconds is ?
Solution :---
it is given that body is projected horizontally with a velocity of 30m/s.
So,
→ ux = 30m/s
→ ax = 0
So,
→ vx = 30m/s . { For whole Time. }
Now, Along vertical axis,
→ uy = 0
→ t = 4 second .
→ ay = 10m/s²
→ vy = ?
we know that , vy = uy +ayt
Putting values we get,
→ vy = 0 + 10*4= 40m/s
So, magnitude of velocity of body after 4s will be :--
→ √{(40)²+(30)²}m/s
→ √(1600+900) m/s
→ √(2500) m/s
→ 50 m/s ...
Hence, Velocity of body After 4 second will be 50m/s.
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