Question

A body is projected horizontally from the top of a tower with a velocity of 30m/s. The velocity of the body

4 seconds after projection is (g = 10m/s^2

)

1) 40m/s 2) 20m/s 3) 50m/s 4) 100m/s​

Answer 1

Answer:

intial horizontal velocity =30 which will remain same with time

initial vertical velocity =0

vertical velocity after 4 sec = gt= 40

• total v=under root of 30to power 2 + 40 to power 2=50m/s