a body is projected horizontally from the top of a tower with 30 metres per second find the velocity of the 4 seconds.take g as 10 m/s
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At ‘A
′
there is no vertical conponent
At ‘B
′
after 4 seconds.
V¹=0+gt=10×4=40 m/s
The resultant velocity V,
V=
√40²+30²
= √1600+900
= √2500
=50m/s
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