A body is projected horizontally from the top of a tower with initial velocity 18 m/s.It hits the ground at angle 45.What is the vertical component of velocity when it strikes the ground
Answers
Answered by
218
u(y) = 0
u(x) - 18 m/s
let the body strikes with v m/s
as given it strikes at 45
so we can write
v cos 45 = 18
v = 18 /cos45
so vertical component will be v sin 45
hence v sin 45 = ( 18/cos45 ) sin45
Thus the vertical component of velocity = 18 m/s
u(x) - 18 m/s
let the body strikes with v m/s
as given it strikes at 45
so we can write
v cos 45 = 18
v = 18 /cos45
so vertical component will be v sin 45
hence v sin 45 = ( 18/cos45 ) sin45
Thus the vertical component of velocity = 18 m/s
Answered by
79
Answer:18 m/sec
Explanation:
Attachments:
Similar questions