a body is projected horizontally from top of a hill with a velocity of 9.8ms what time elapses before vertical velocity is twice the horizontal velocity
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1
Answer:
the time elapses before vertical valocity is twice the horizontel valocity is 10'
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3
Hello mate..
Here Is Your Answer:
Vy = 2Ux
gt = 2 × U
9.8 × t = 2 × 9.8
(as 9.8 and 9.8 gets cancelled..)
t = 2
HOPE THIS HELPS YOU..
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