Question

a body is projected horizontally with 10 per metresecond from the top of a tower of the height 19.6 metres the distance at which it falls from the foot of the Tower is ​

Answer 1

Answer:

20 meters.

Explanation:

initial velocity (u) = 10m/s

height = 19.6 m

Time required to complete projectile motion (t) = √(2h/g)

Therefore t = √[(2*19.6)/9.8]

t = 2 sec.

Horizontal Range (R) = u * t

R = 10 * 2 = 20 meters.

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