A body is projected horizontally with a velocity of 10m/s from the top of the tower of height 19.6m.The distance at which it falls from the foot of the tower is
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23
u=10m/s
h=19.6m
d=?
t=√2h/g
t=√2×19.6/9.8=2sec
d=10×2=20m
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4
Answer:
20
Explanation:
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