Question

A body is projected horizontally with initial velocity 20m/s from top of a tower of height 100m.

Assume acceleration due to gravity is 10m/s2

. Calculate

1) time taken by the body to hit the ground

2) distance of the point from bottom of tower where the body hits the ground​

Answer 1

Answer:

1 answer 138920.99 sec

2. 3153861.36min

Explanation:

correct answer

Answer 2

Answer:

1)in the vertical direction

s=100m

a=10m/s²

u=0. body is projected in the horizontal direction

t=?

s=ut+at²/2

s=0+10(t²)/2

s=5t²

100/5=t²

t=√20=2√5s

2)in horizontal direction

a=0

u=20m/s

t=2√5s

s=?

s=ut+at²/2

s=20*2√5+0

s=40√5m