Question

a body is projected horizontally with speed u from a tower of height H the magnitude of velocity with which a body crosses the height H by 2 will be​

Answer 1

Answer:

v = √u² + 10H²

Explanation:

H/2 = gt²/2  , 10 t ² = H , t = √H/10

vx = u , vy = gt = H√10

v = √u² + 10H²