Question

a body is projected in a vertical direction. the altitude y is given by y =10t^2 -9t+5 . Calculate the initial velocity of the body.​

Answer 1

Answer:

${\orange{\overbrace{ \red{ \overbrace{\red{\underbrace \color{blue} {\underbrace \color{black} {\fcolorbox{magenta}{lime}{\fcolorbox{red}{black}{\fcolorbox{pink}{pink}{ \fcolorbox{blue}{blue}{{\bf{{{{\pink{ Question࿐}}}}}}}}}}}}}}}}}}$

a body is projected in a vertical direction. the altitude y is given by y =10t^2 -9t+5 . Calculate the initial velocity of the body.

$\huge \rm \red{AnSwEr}$

Refers to the attachment

Answer 2

Answer:

initial velocity = -9m/s

Explanation:

y = 10t² - 9t + 5

velocity is the change in velocity with respect to time.

dy/dt = 20t - 9

so, velocity at time = 0 = initial velocity

initial velocity = 20(0) - 9

initial velocity = -9m/s

where -ve sign represent the direction.