Question

A body is projected in a verticle direction, the altitude y is given by y=10t²-9t+5
Calculate the initial velocity of the body​

Answer 1

Answer:

For example

Explanation:

y = 8t - 5t²

differentiate wrt time

dy/dt = 8 -10t

we know, change in position per unit time is called , velcity .

e.g dy/dt = Vy

Vy = 8 -10t

now at t = 0 ( initially )

Vy =8 -10× 0 = 8

x = 6t

differentiate wrt time

dx/dt = 6

similarly , dx/dt = Vx =6

now,

V = Vx i + Vy j

= 8 i + 6 j

magnitude of velocity =| V | =√(8² + 6²) =10 m/s