Question

A body is projected in air such that fits horizontal range is equal to maximum height. It's angle of projection with horizontal theta is such that 1. SinO=3/5 2. TanO =4 3. Cos O=3/5 4.=45° Here O is equal to theta

Answer 1

Given :

The horizontal range of the projectile is equal to the maximum height attained by the projectile .

To find :

SIn, cosine or tan function of angle of projection or angle itself .

Solution :

range = ( $u^2$ sin2θ ) / g

height = ( $u^2$ si$n^2$θ ) / 2g

where , u is initial velocity and θ is the angle of projection .

Now ,

range = height

=> ( $u^2$ sin2θ ) / g = ( $u^2$ si$n^2$θ ) / 2g

=> 2 cosθ = sinθ / 2

=> tanθ = 4

The angle of projection with horizontal theta is such that tanθ = 4 .