Question

a body is projected in such way that its range and maximum height are equal. find the angle of projection

Answer 1

Answer:

Answer given below

Explanation:

given

horizontal range=u²sin 2Ф/g

maximum height=u²sin² Ф / 2g

horizontal range = 3× maximum height

u²sin 2Ф / g =3×u²sin² Ф / 2g

sin 2Ф=2sinФ.cosФ

2sinФ.cosФ= 3 / 2.sin²Ф

tan Ф= 4 / 3

Ф=tan⁻¹( 4 / 3 )

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