A body is projected in the horizontal direction with speed 30m/s from a certain height of 125m Calculate the speed of the body after 4 a) 30m/s b) 40m/s c) 50m/s d) 45m/s Ans:
Answers
Answered by
0
Answer:
=45
3
m
Explanation:
Here u=30ms
−1
, Angle of projection, θ=90−30=60
∘
Maximum height,
H=
2g
u
2
sin
2
θ
=
2×10
30
2
sin
2
60
∘
=
20
900
×
4
3
=
4
135
m
Time of flight, T=
g
2usinθ
=
10
2×30×sin60
∘
=3
3
s
Horizontal range = R=
g
u
2
sin2θ
=
10
30×30×2sin60
∘
cos60
∘
Answered by
0
Answer:
30 is the answer
hope it will help u
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