Question

A body is projected in to the air in the vertically upward direction, find the height at which its potential and kinetic energies are equal.
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Answer 1

Answer:

in the middle of atmosphere where kinetic energy and potential energy are same as the kinetic energy occurs due to movement of some object and potential energy occurs at rest position

Answer 2

Answer:

The height is $h=\frac{v^{2} }{2g}$

Explanation:

It is given that a body is projected in to the air in the vertically upward direction.

We need to find the height at which its potential and kinetic energies are equal.

Let the height be $h$, mass be $m$ and $g$ be acceleration due to gravity.

At that point

Kinetic Energy = Potential energy

$mv^{2}/2 =mgh$

$v^{2}=2gh$

$h=\frac{v^{2} }{2g}$

The height at which its potential and kinetic energies are equal is $h=\frac{v^{2} }{2g}$.

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