Question

A body is projected into air with velocity 20 m/s at an angle 60°. Find its position after 1 second
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Answer 1

Answer:

10, 12.3 is correct answer

Mark the answer brainliests please

Answer 2

Answer:

We will divide the Projectile motion into 2 simultaneously occuring 1D motions.

Along X axis :

$\sf{ \therefore \: x = u \cos( \theta) \times t}$

$\sf{ \implies \: x = 20 \cos( 60 \degree) \times 1}$

$\sf{ \implies \: x = 20 \times \dfrac{1}{2} \times 1}$

$\sf{ \implies \: x = 10 \: m}$

Along Y axis :

$\sf{ \therefore \: y = u \sin( \theta) t - \frac{1}{2} g {t}^{2}}$

$\sf{ \implies \: y = 20 \sin( 60 \degree) \times 1- ( \frac{1}{2} \times 10 \times {1}^{2}} )$

$\sf{ \implies \: y = 20 \times \frac{ \sqrt{3} }{2} - 5}$

$\sf{ \implies \: y =17.32 - 5}$

$\sf{ \implies \: y =12.32 \: m}$

So , coordinate will be :

$\boxed{ \red{ \bold{ \sf{ \huge{(x,y) = (10,12.32)}}}}}$