A body is projected to attend the maximum range.
The ratio of maximum range
to maximum height is
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Answer:
to obtain the maximum range the angle should be 45 degrees
maximum range = u^2 sin 2θ /g by keeping θ = 45 range = u^2 sin 90/g
we know sin 90 = 1 ,so maximum range = u^2/g
maximum height is obtained by keeping θ = 45 in formula u^2 sin^2 θ /2g
maximum height = by calculating = u^2/4g
Then ratio of maximum range to maximum height is = u^2/g / u^2/4g
=> 4
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