Question

a body is projected up so that it can reach maximum height h what is its height from the ground when the velocity is half the maximum velocity..
(1) 0.5 H
(2) 0.25 H
(3) 0.75 H
(4) 0.66 H



answer was given 0.75 but i get 0.25 plz some one help​

Answer 1

Answer:

option 2 is right answer

Explanation:

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Answer 2

• initial velocity will be maximum...
• at maximum its momentarily at rest.

lets slove!!

• ${v}^{2} = {u}^{2} + 2as$
• $0 = {v}^{2} - 2gh$
• $v = \sqrt{2gh}$

Now according to second case...

• (v/2)^2=v^2 -2gh1
• $\frac{ {v}^{2} }{4} = {v}^{2} - 2g h_{1}$
• $\frac{3 {v}^{2} }{4} = 2g h_{1}$
• $h_{1} = \frac{ 3{v}^{2} }{8g}$
• $h_{1} = \frac{3 \times 2gh}{2g4}$
• $h_{1} = \frac{3h}{4}$
• h1 =0.75 H

hope it helps..

Good luck ♧♧