A body is projected up such that its position vector varies with time as r = { 3thati + (4 t - 5t^2)hatj} m. Here, t is in seconds. Find the time and x-coordinate of particle when its y-coordinate is zero.
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Answer:0.8sec
Explanation:
They had been given that y cordinate as r =3ti+4t-5t.tj m
So y coordinate is 4t-5t.t =0
So by solving it we get t=0.8 sec
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hope it is correct
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