a body is projected up with 3/4th of the escape velocity from earth surface the height reached by the body is
Answers
Answered by
1
heya
good evening,
escape velocity of earth is 11.186 km/s
so, in one second the body will be at height,
we know,
speed = distance/time
=>distance= speed×time
![\frac{3}{4} \times 11.186 \frac{3}{4} \times 11.186](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B4%7D+%5Ctimes+11.186)
![= 8.3895 \: kms = 8.3895 \: kms](https://tex.z-dn.net/?f=+%3D+8.3895+%5C%3A+kms)
hope this help
please like it
good evening,
escape velocity of earth is 11.186 km/s
so, in one second the body will be at height,
we know,
speed = distance/time
=>distance= speed×time
hope this help
please like it
akshatit:
mark as the brainlist
Similar questions
English,
8 months ago
Computer Science,
8 months ago
Math,
8 months ago
Math,
1 year ago
Physics,
1 year ago