Question

A body is projected up with a
velocity u. What is the maximum
height reached ? What is the time taken to reach highest point?​

Answer 1

Explanation:

Velocity at the maximum height v=0

Acceleration a=−g

Using v

2

−u

2

=2aH

∴ 0−u

2

=2(−g)H

⟹ H=

2g

u

2

We get

H

1

H

2

=

u

1

2

u

2

2

or

H

H

2

=

u

2

(2u)

2

=4

⟹ H

2

=4H