A BODY IS PROJECTED UP WITH AN INITIAL VELOCITY OF 10M/S. HOW MUCH TIME IT WILL TAKE TO REACH THE STARTING POINT?
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s=ut + 0.5 a t^2
At starting point, displacement s= 0
0= 10 t + 0.5 x -9.81 x t^2
t ( 10 - 4.905 t ) = 0
t = 0 or 4.905 t = 10
Ans t = 2.04 s (3s.f.)
At starting point, displacement s= 0
0= 10 t + 0.5 x -9.81 x t^2
t ( 10 - 4.905 t ) = 0
t = 0 or 4.905 t = 10
Ans t = 2.04 s (3s.f.)
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