Question

A body is projected up
with velocity 4om/s upwards
then find Distance
travelled in 4 sec
​

Answer 1

hope this is helpful...

Answer 2

Step-by-step explanation:

• Initial velocity = 40 m/s
• Time = 4 s
• Distance = ?
• Acceleration = -10 m/s²

We know that,

$\boxed{\sf s=ut + \dfrac{1}{2}at^2}$

$\longmapsto \sf (40)(4) + \dfrac{1}{2}×(-10)×(4)^2$

$\longmapsto \sf 160-5×16$

$\longmapsto \sf 160-80$

$\longmapsto \sf 80 \: m$

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