Question

A body is projected upward with initial velocity “u”. Calculate the time for which it
remains in air

Answer 1

Answer:

v=u+gt

at highest distance,v=0,and g acts in opposite direction.

So,

0=u−gt

t=

g

u

since time taken to ascent and descent is same.

So, the total time(t) is

g

2u

for which it remain in air.

Answer 2

Explanation:

v=u+gt

at highest distance,v=0,and g acts in opposite direction.

So,

0=u−gt

t=

g

u

since time taken to ascent and descent is same.

So, the total time(t) is

g

2u

for which it remain in air.

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