Question

A body is projected upward with speed 60m/s. Find the distance travelled by it in 6th second.(g=10m/s^2)

Answer 1

Distance travelled in 6th second will be 55m
(This is the distance travelled only in 6th second.....rest all other seconds will have different rations of distance in the form of 1:3:5:7:........)
NOTE: This distance is not the distance travelled in successive second.

Answer 2

From the Equation
Time to reach max height=u/g
We get
Time to reach max height=60/10
=6 s
So the path of the ball will be like this:

6s
5s. 7s
4s. 8s
3s. 9s
2s. 10s
1s. 11s
0s(start). 12s(end)

So the distance Traveled in 6th second is the highest maximum height reached by the body.

From Equation
Maximum Height reached =(u^2/2g)
=(60^2)/2×10=3600/20=180m

Therefore The distance traveled by the body in 6th second is 180m.

Cheers.