Physics, asked by aravindtupakula3609, 9 months ago

a body is projected upwards reaches the max height 40 m and it returns to the initial position .then distance and displacement of the body are

Answers

Answered by rssingh64
2

Answer:

Since it was thrown up vertically up, and as it travels vertically up tiil it came to rest, distance travelled up is the height h.

As it returned vertically down , through a distance h, the total distance is h + h = 2h.

Since it was thrown up vertically up, and as it travels vertically up tiil it came to rest, displacement was the height h.

As it returned vertically down , through a displacement -h , the total displacement is h -h = 0

Or as the starting and finishing points are the same displacement is zero

Explanation:

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