Question

a body is projected upwards reaches the max height 40 m and it returns to the initial position .then distance and displacement of the body are
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Answer 1

Answer:

Given:

Body is projected upwards such that it reaches a max height of 40 m . Then it comes back to its initial position.

To find:

Distance and displacement of the body.

Concept:

Distance is the total path length covered by an object in a specified time interval. It's a scalar Quantity and hence always positive.

Displacement is the shortest length between the starting and the stopping point. It's a vector Quantity . It can be negative , zero or positive.

Calculation:

$distance = 2 \times (max \: height)$

$= > distance = 2 \times (40)$

$\boxed{ = > distance = 80 \: m}$

Displacement will be zero as the starting and stopping point are same .

$\boxed{displacement = 0 \: m}$