Question

A body is projected upwards with a velocity of 30 m s-1 at an angle of 30° with the horizontal. Determine (a) the time of flight (b) the range of the body and (c) the maximum height attained by the body.

Answer 1

Known:
vo=30 m/s
α =30°
Asked:
-Time flight (tf) 
-xm
-Hm
Answer:
Consider g=10 m/s²

-Time flight:
tf=2vo.sinα
        g
  =2.30.sin 30
        10
  =2.30.¹/₂
       10
  =2.1,5 second
  =3 second
-Rang of body :
Xm=vo²sin2α
              g
      =30².sin(2x30)
            10
      =900.sin 60
            10
      =900.¹/₂√3
            10
      =45√3 meter

-The maximum Height
Hm=vo².sin²α
           2g
      =30².sin²(30)
          20
      =900.(¹/₂)²
           20
      =45
         4
      =11,25 meter

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