Question

A body is projected upwards with a velocity u. It it passes through a certain point above the ground after T1 second the time after which the body pass through the same point during the return journey is​

Answer 1

Answer:

Let the starting point be A, point crossed by the ball be B and final point from where the ball returns be C.

For AC, v=0, u=u, and total time= t

0= u-gt

Or t= u/g ---eq.1

Now from A to B, time = t1 & from B to C, t= t2.

t = t1+t2 or t2 = t - t1.

But the ball comes back to the point B from C,

Implies that t2= 2(t- t1)

= 2(u/g - t1) is the final answer.

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Explanation: