Question

A body is projected ventricle upwords with a velocity of 20m/s. calculate maximum hight obtained by a a body. time taken to reach maximum height by using (g=10m/s)​

Answer 1

Given:-

• Initial velocity ,u = 20m/s

• Final velocity ,v = 0m/s

• Acceleration due to gravity ,g = 10m/s²

To Find:-

• Maximum height attained by body ,h

• Time taken to reach maximum height ,t

Solution:-

Using 3rd Equation of Motion

• v² = u² +2ah

where,

v is the final velocity

a is the acceleration

u is the initial velocity

h is the height

Substitute the value we get

→ 0² = 20² + 2×(-10) ×h

→ 0 = 400 + (-20) ×h

→ -400 = -20×h

→ h = -400/-20

→ h = 400/20

→ h = 20 m

Therefore, the maximum height attained by the body is 20 Metres.

Now, calculating the time taken .

You can also use second Equation of Motion .

By using 1 st Equation of Motion

• v = u + at

Substitute the value we get

→ 0 = 20 + (-10) ×t

→ -20 = -10×t

→ t = -20/-10

→ t = 20/10

→ t = 2s

Therefore,the time taken by the body to reach maximum height is 2 second.

Answer 2

$\huge{\boxed{\rm{Question}}}$

A body is projected ventricle upwords with a velocity of 20m/s . Calculate maximum hight obtained by a body. Time taken to reach maximum height by using (g=10m/s²)

$\huge{\boxed{\rm{Answer}}}$

$\large{\boxed{\boxed{\sf{Given \: that}}}}$

• Initial velocity = 20 m/s

• Final velocity = 0 m/s

• Acceleration due to gravity = 10 m/s²

$\large{\boxed{\boxed{\sf{To \: find}}}}$

• Maximum height attained by the body.

$\large{\boxed{\boxed{\sf{Solution}}}}$

• Maximum height attained by the body = 20 m

• Time taken to reach maximum height = 2 seconds

$\large{\boxed{\boxed{\sf{We \: also \: write \: as}}}}$

• Acceleration as a

• Time as t

• Initial velocity as u

• Final velocity as v

• Gravity as g

• Height as h

• Force as f

$\large{\boxed{\boxed{\sf{What \: does \: the \: question \: says}}}}$

$\large{\boxed{\boxed{\sf{Let's\: understand \: the \: concept \: 1st}}}}$

• This question says that there is a body which have initial velocity = 20 m/s and it's final velocity will be 0 m/s . After that it says that it's Acceleration due to gravity become 10 m/s². Now there question ask us to find the maximum hight obtained by a body and time taken to reach maximum height also.

$\large{\boxed{\boxed{\sf{How \: to \: solve \: this \: question}}}}$

$\large{\boxed{\boxed{\sf{Let's\: see \: the \: procedure \: now}}}}$

• To solve the first part of the question that is to calculate maximum hight obtained by a a body. We have to follow this procedure – To solve this firstly we have to learn the formula of Newton's third law of motion nd we know the Newton third law of motion is v² = u² + 2ah. After that we have to put the values according to this formula. After that we get our final result of 1st part that question that is 20 metres.Hence we get our first result.

• To solve the second part of the question we have to know the formula of Newton's first law of motion nd the formula is v = u + at after that we have to put the values then we get our final result that is 2 seconds. It's the answer of 2nd part of this question.

$\large{\boxed{\boxed{\sf{Full \: solution}}}}$

To solve this question's first part we have to follow the formula of Newton's third law of motion and we know what is the formula of Newton's third law of motion . The formula is given below –

$\small\pink{\texttt{v² = u² + 2ah}}$

Where these values means -

• v means final velocity.

• u means initial velocity.

• a means acceleration.

• h means height.

$\large\purple{\texttt{Putting the values we get}}$

❍ v² = u² + 2ah

❍ 0² = 20² + 2 × (-10) × h

❍ 0² = 400 + (-20) × h

❍ -400 = -20 × h

❍ h = -400 / -20

❍ h = 400 / 20

❍ h = 20 m

Hence, 20 metres is the maximum height obtained by body.

______________________________

To solve this question's second part we have to follow the formula of Newton's first law of motion and we know what is the formula of Newton's first law of motion . The formula is given below –

$\small\pink{\texttt{v = u + at}}$

Where these values means -

• v means final velocity.

• u means initial velocity.

• a means acceleration.

• t means time.

$\large\purple{\texttt{Putting the values we get}}$

❍ v = u + at

❍ 0 = 20 + (-10) × t

❍ -20 = -10 × t

❍ t = -20/-10

❍ t = 20/10

❍ t = 2 seconds.

Hence, 2 seconds is the time taken to reach maximum height.

______________________________

$\huge{\boxed{\rm{More \: knowledge}}}$

1st Newton's law of motion definition

In the first law, an object will not change its motion unless a force acts on it.

2nd Newton's law of motion definition

In the second law, the force on an object is equal to its mass times its acceleration.

3rd Newton's law of motion definition

In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

$\huge{\boxed{\rm{More \: knowledge}}}$

1st Newton's law of motion formula

v = u + at

2nd Newton's law of motion formula

f = ma

3rd Newton's law of motion formula

v² = u² + 2ah

Hope it's helpful

Thank you :)