Question

A body is projected vertical ly upward with a velocity of 10 m/s.it reaches maximum height h at time t. in time t/2 , the height covered is??​

Answer 1

Answer:

5m is the correct ans

Explanation:

Taking g=10m/s^2

therefore,applying the eqn of motio

v^2=u^2-2gh

at max ht v=0

and u = 10m/s

thus, (0)^2=(10)^2-2(10)(h)

h=100/20 =>5m :) mark as brainliest if found helpful